Como posso ler um arquivo XML e armazenar os dados em XML em nossa tabela no SQL Server 2008?
Como posso ler um arquivo XML e armazenar os dados em XML em nossa tabela no SQL Server 2008?
Respostas:
Este XML de nó de análise baseado. É diferente ler atributos, mas não é tão comum
Eu tive isso por aí como uma demonstração com 3 consultas XPath ligeiramente diferentes
DECLARE @foo XML
SELECT @foo = N'
<harrys>
<harry>
<fish>0.015000000000</fish>
<bicycle>2008-10-31T00:00:00+01:00</bicycle>
<foo>ü</foo>
</harry>
<harry>
<fish>0.025000000000</fish>
<bicycle>2008-08-31T00:00:00+01:00</bicycle>
<foo>ä</foo>
</harry>
</harrys>
'
SELECT
CAST(CAST(y.item.query('data(fish)') AS varchar(30)) AS float),
CAST(LEFT(CAST(y.item.query('data(bicycle)') AS char(25)), 10) AS smalldatetime),
CAST(y.item.query('data(foo)') AS varchar(25))
FROM
@foo.nodes('/*') x(item)
CROSS APPLY
x.item.nodes('./*') AS y(item)
SELECT
CAST(CAST(x.item.query('data(fish)') AS varchar(30)) AS float),
CAST(LEFT(CAST(x.item.query('data(bicycle)') AS char(25)), 10) AS smalldatetime),
CAST(x.item.query('data(foo)') AS varchar(25))
FROM
@foo.nodes('harrys/harry') x(item)
SELECT
CAST(CAST(y.item.query('data(fish)') AS varchar(30)) AS float),
CAST(LEFT(CAST(y.item.query('data(bicycle)') AS char(25)), 10) AS smalldatetime),
CAST(y.item.query('data(foo)') AS varchar(25))
FROM
@foo.nodes('/harrys') x(item)
CROSS APPLY
x.item.nodes('./harry') AS y(item)
Eu tentei com a resposta acima. Tente,
XML:
<?xml version="1.0" encoding="utf-8" ?>
- <FundingSought xml:lang="en">
- <Fund>
<FundName>sdfdsfd</FundName>
<FundValue>1</FundValue>
</Fund>
- <Fund>
<FundName>dfdgfdg</FundName>
<FundValue>2</FundValue>
</Fund>
- <Fund>
<FundName>fghghh</FundName>
<FundValue>3</FundValue>
</Fund>
- <Fund>
<FundName>sdfdgg</FundName>
<FundValue>4</FundValue>
</Fund>
- <Fund>
<FundName>hgfhh</FundName>
<FundValue>5</FundValue>
</Fund>
- <Fund>
<FundName>fghgh</FundName>
<FundValue>6</FundValue>
</Fund>
- <Fund>
<FundName>ghhhh</FundName>
<FundValue>7</FundValue>
</Fund>
- <Fund>
<FundName>hfghh</FundName>
<FundValue>8</FundValue>
</Fund>
</FundingSought>
SQL:
CREATE TABLE #XmlImportTest(
xmlFileName VARCHAR(300) NOT NULL,
xml_data XML NOT NULL
)
GO
DECLARE @xmlFileName VARCHAR(300)
SELECT @xmlFileName = 'C:\FundingSought.xml'
--– dynamic sql is just so we can use @xmlFileName variable in OPENROWSET
EXEC('INSERT INTO #XmlImportTest(xmlFileName, xml_data)
SELECT ''' + @xmlFileName + ''', xmlData
FROM(
SELECT *
FROM OPENROWSET (BULK ''' + @xmlFileName + ''', SINGLE_BLOB) AS XMLDATA
) AS FileImport (XMLDATA)
')
GO
DECLARE @foo XML
SET @foo = (SELECT xml_data from #XmlImportTest)
SELECT
CAST(y.item.query('data(FundName)') AS varchar(30)),
CAST(y.item.query('data(FundValue)') AS char(25))
FROM
@foo.nodes('/*') x(item)
CROSS APPLY
x.item.nodes('./*') AS y(item)
Necromancing:
Da sequência:
SELECT
--myTempTable.XmlCol.value('.', 'varchar(36)') AS val
myTempTable.XmlCol.query('./ID').value('.', 'varchar(36)') AS ID
,myTempTable.XmlCol.query('./Name').value('.', 'nvarchar(MAX)') AS Name
,myTempTable.XmlCol.query('./RFC').value('.', 'nvarchar(MAX)') AS RFC
,myTempTable.XmlCol.query('./Text').value('.', 'nvarchar(MAX)') AS Text
,myTempTable.XmlCol.query('./Desc').value('.', 'nvarchar(MAX)') AS Description
FROM
(
SELECT
CAST('<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<data-set>
<record>
<ID>1</ID>
<Name>A</Name>
<RFC>RFC 1035[1]</RFC>
<Text>Address record</Text>
<Desc>Returns a 32-bit IPv4 address, most commonly used to map hostnames to an IP address of the host, but it is also used for DNSBLs, storing subnet masks in RFC 1101, etc.</Desc>
</record>
<record>
<ID>2</ID>
<Name>NS</Name>
<RFC>RFC 1035[1]</RFC>
<Text>Name server record</Text>
<Desc>Delegates a DNS zone to use the given authoritative name servers</Desc>
</record>
</data-set>
' AS xml) AS RawXml
) AS b
--CROSS APPLY b.RawXml.nodes('//record/ID') myTempTable(XmlCol);
CROSS APPLY b.RawXml.nodes('//record') myTempTable(XmlCol);
De arquivo:
SELECT
--myTempTable.XmlCol.value('.', 'varchar(36)') AS val
myTempTable.XmlCol.query('./ID').value('.', 'varchar(36)') AS ID
,myTempTable.XmlCol.query('./Name').value('.', 'nvarchar(MAX)') AS Name
,myTempTable.XmlCol.query('./RFC').value('.', 'nvarchar(MAX)') AS RFC
,myTempTable.XmlCol.query('./Text').value('.', 'nvarchar(MAX)') AS Text
,myTempTable.XmlCol.query('./Desc').value('.', 'nvarchar(MAX)') AS Description
FROM
(
SELECT CONVERT(XML, BulkColumn) AS RawXml
FROM OPENROWSET(BULK 'D:\username\Desktop\MyData.xml', SINGLE_BLOB) AS RowSetName
) AS b
CROSS APPLY b.RawXml.nodes('//record') myTempTable(XmlCol)
por exemplo
DECLARE @bla varchar(MAX)
SET @bla = 'BED40DFC-F468-46DD-8017-00EF2FA3E4A4,64B59FC5-3F4D-4B0E-9A48-01F3D4F220B0,A611A108-97CA-42F3-A2E1-057165339719,E72D95EA-578F-45FC-88E5-075F66FD726C'
-- http://stackoverflow.com/questions/14712864/how-to-query-values-from-xml-nodes
SELECT
x.XmlCol.value('.', 'varchar(36)') AS val
FROM
(
SELECT
CAST('<e>' + REPLACE(@bla, ',', '</e><e>') + '</e>' AS xml) AS RawXml
) AS b
CROSS APPLY b.RawXml.nodes('e') x(XmlCol);
Então você pode ter uma função como
SELECT * FROM MyTable
WHERE UID IN
(
SELECT
x.XmlCol.value('.', 'varchar(36)') AS val
FROM
(
SELECT
CAST('<e>' + REPLACE(@bla, ',', '</e><e>') + '</e>' AS xml) AS RawXml
) AS b
CROSS APPLY b.RawXml.nodes('e') x(XmlCol)
)
Vou apenas adicionar uma resposta para que você saiba que tem outra opção. Você também pode usar o OPENXML para ler dados xml. Essa era a maneira de fazer isso nas versões mais antigas do SQL Server. Não é perfeito, mas funciona. E é fácil abusar :-). Basta comparar os planos de dois xmls idênticos tratados com consultas XPATH (resposta de gbn) em comparação com OPENXML ou OPENROWSET. Vou usar um exemplo do artigo do MSDN agora, mas você pode obter uma imagem completa:
DECLARE @idoc int
DECLARE @doc varchar(1000)
SET @doc ='
<ROOT>
<Customer CustomerID="VINET" ContactName="Paul Henriot">
<Order CustomerID="VINET" EmployeeID="5" OrderDate="1996-07-04T00:00:00">
<OrderDetail OrderID="10248" ProductID="11" Quantity="12"/>
<OrderDetail OrderID="10248" ProductID="42" Quantity="10"/>
</Order>
</Customer>
</ROOT>'
--Create an internal representation of the XML document.
EXEC sp_xml_preparedocument @idoc OUTPUT, @doc
-- Execute a SELECT statement that uses the OPENXML rowset provider.
SELECT *
FROM OPENXML (@idoc, '/ROOT/Customer',1)
WITH (CustomerID varchar(10),
ContactName varchar(20))